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What amount of pure acid must be added to 300 mL of a 50% acid solution to produce a 75% acid solution?

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Answer:

you need to add 300 mL of pure acid to the 300 mL of the 50% acid solution to produce a 75% acid solution.

Explanation:

Let x be the amount (in mL) of pure acid to be added.

The amount of acid in the 300 mL of 50% solution is 0.50 * 300 = 150 mL of pure acid.

When you add x mL of pure acid to this solution, the total volume of the mixture becomes 300 mL + x mL.

The equation for the amount of acid in the final mixture can be written as:

0.50 * 300 (acid from the original solution) + 1.00 * x (acid from the pure acid added) = 0.75 * (300 + x) (acid in the final 75% solution)

Now, let's solve for x:

150 + x = 0.75 * (300 + x)

150 + x = 225 + 0.75x

Now, subtract 0.75x from both sides:

0.25x = 225 - 150

0.25x = 75

Now, divide by 0.25 to isolate x:

x = 75 / 0.25

x = 300

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