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Find the equation of the line containing the point P(2, 3) and perpendicular to the graph of y = 3/2 x-5

User Bjnr
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1 Answer

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Answer:

Explanation:

y = - 2/3x + 13/3

Slope: - 2/3 (negative reciprocal). Point: (2,3)

y-y = m(x-x)

y - 3 = - 2/3 (x - 2)

y - 3 = -2/3x + -4/3

y = -2/3x + 13/3

User Idistic
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