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How many atoms of oxygen are in a 0.78 mol sample of CaCO_3?

User Bhassel
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Answer:

9.39 x 10^23 oxygen atoms

Step-by-step explanation:

Each molecule of CaCO3 contains 3 oxygen atoms. We can determine the number of CaCO3 molecules from the 0.78 moles.

(0.78 moles)*(6.022x10^23 molecules/mole) = 4.70 x 10^23 CaCO3 molecules

(4.70 x 10^23 CaCO3 molecules)*(2 O atoms/CaCO3 molecule) = 9.39 x 10^23 oxygen atoms

User Jeffery Thomas
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