Answer:a) Probability of getting a 3 = 1/6
b) Probability of getting less than 3 = 1/3
c) Probability of getting an even number = 1/2
d) Probability of getting 7 = 0
Explanation:
When rolling an ordinary six-sided die, there are 6 possible outcomes, each corresponding to the number of dots on its upper face, which are 1, 2, 3, 4, 5, and 6. Let's calculate the probability for each of the given scenarios:
a) Probability of getting a 3:
There is only 1 way to roll a 3, and there are 6 equally likely outcomes in total.
Probability of getting a 3 = (Number of ways to get a 3) / (Total number of outcomes) = 1/6
b) Probability of getting less than 3 (i.e., 1 or 2):
There are 2 ways to get a 1 or 2, and there are 6 equally likely outcomes in total.
Probability of getting less than 3 = (Number of ways to get 1 or 2) / (Total number of outcomes) = 2/6 = 1/3
c) Probability of getting an even number:
Even numbers on a die are 2, 4, and 6. There are 3 ways to get an even number, and there are 6 equally likely outcomes in total.
Probability of getting an even number = (Number of ways to get an even number) / (Total number of outcomes) = 3/6 = 1/2
d) Probability of getting 7:
It's impossible to roll a 7 on a standard six-sided die because the highest number on the die is 6. So, the probability of getting 7 is 0.
To summarize:
a) Probability of getting a 3 = 1/6
b) Probability of getting less than 3 = 1/3
c) Probability of getting an even number = 1/2
d) Probability of getting 7 = 0