For the sample, the minimum mass of solid KI is 2.438 g and the minimum volume of 2.90 M HCl is 6.08 mL.
How to find minimum mass and volume?
Determine the balanced chemical equation:
KIO₃ + 5 KI + 6 HCl → 3 I₂ + 6 KCl + 3 H₂O
Calculate the moles of potassium iodate:
Moles KIO₃ = Mass / Molar mass
= 0.6303 g / 214.01 g/mol
= 0.00294 mol
Calculate the minimum mass of solid KI needed:
From the balanced equation, 5 moles KI react with 1 mole KIO₃.
Therefore, minimum moles KI needed
= 5 × 0.00294 mol
= 0.0147 mol
Minimum mass of KI
= Moles × Molar mass
= 0.0147 mol × 166.01 g/mol
= 2.438 g
Calculate the minimum volume of 2.90 M HCl needed:
From the balanced equation, 6 moles HCl react with 1 mole KIO₃.
Therefore, minimum moles HCl needed
= 6 × 0.00294 mol
= 0.01764 mol
Minimum volume of HCl
= Moles / Molarity
= 0.01764 mol / 2.90 M
= 0.00608 L
= 6.08 mL