Question

What would be the spectator ions for the reaction between NH4OH and KI

Answer 1

K+ and OH-.

Step-by-step explanation:

The reaction between NH4OH (ammonium hydroxide) and KI (potassium iodide) can be represented by the following equation:

NH4OH + KI → NH4I + KOH

In this reaction, NH4OH donates a proton (H+) to KI, forming NH4I (ammonium iodide) and KOH (potassium hydroxide). The NH4+ ion from NH4OH and the I- ion from KI combine to form NH4I, while the K+ ion from KI and the OH- ion from NH4OH combine to form KOH.

The spectator ions in this reaction are the ions that do not participate in the actual chemical reaction and remain unchanged throughout the process. In this case, the spectator ions are K+ from KI and OH- from NH4OH. They do not change their chemical identities and are present on both sides of the reaction equation.

Therefore, the spectator ions for the reaction between NH4OH and KI are K+ and OH-.

Answer 2

Answer: K+ and OH-

Step-by-step explanation:

To determine the spectator ions for the reaction between NH4OH and KI, we need to identify the ions that remain unchanged and do not participate in the overall reaction.

First, let's write the balanced equation for the reaction between NH4OH and KI:

NH4OH + KI → NH4I + KOH

In this reaction, NH4OH (ammonium hydroxide) is a weak base that dissociates into NH4+ (ammonium) and OH- (hydroxide) ions. KI (potassium iodide) is a soluble salt that dissociates into K+ (potassium) and I- (iodide) ions.

Based on the balanced equation, we can see that the NH4+ and I- ions react to form NH4I, while the K+ and OH- ions form KOH. Therefore, the spectator ions in this reaction are the K+ and OH- ions.

These spectator ions are present on both sides of the equation and do not undergo any chemical changes. They simply remain in the solution without being consumed or produced during the reaction.

In summary, the spectator ions for the reaction between NH4OH and KI are K+ and OH-.

I hope this helps :)