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What is an equation for the line that passes through (6, −5) and (−8, 16)?

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Answer:

y = -3/2 + 4

Explanation:

Given two points through which a line passes, we can find its equation in slope-intercept form, whose general equation is given by:

y = mx + b, where

  • m is the slope,
  • and b is the y-intercept.

Finding the slope (m):

We can find the slope using the slope formula, which is given by:

m = (y2 - y1) / (x2 - x1), where

  • m is the slope,
  • (x1, y1) is one point on the line,
  • and (x2, y2) is another point.

Thus, we can find the slope (m) by substituting (6, -5) for (x1, y1) and (-8, 16) for (x2, y2) in the slope formula:

m = (16 - (-5)) / (-8 - 6)

m = (16 + 5) / (-14)

m = 21 / -14

m = -3/2

Thus, the slope is -3/2.

Finding the y-intercept (b):

Now we can find the y-intercept (b) by substituting -3/2 for m and (6, -5) for (x, y) in the slope-intercept form:

-5 = -3/2(6) + b

-5 = -18/2 + b

(-5 = -9 + b) + 9

4 = b

Thus, the y-intercept is 4.

Writing the equation of the line in slope-intercept form:

Therefore, y = -3/2 + 4 is the equation of the line in slope-intercept that passes through (6, -5) and (-8, 16)

User Mariano DAngelo
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