Let's simplify each of these expressions:
(a) e^ln(√6):
Since ln and e are inverse functions, e^ln(√6) simplifies to just √6.
(b) e^ln(1):
ln(1) equals 0 because e^0 equals 1. So, e^ln(1) simplifies to 1.
(c) 10^log(19):
Since log base 10 and 10^x are inverse functions, 10^log(19) simplifies to just 19.
So, the simplified expressions are:
(a) √6
(b) 1
(c) 19