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Determine the number of solutions for 3(2x + 5) – 6x = 40

2 Answers

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To solve the equation, isolate x.


\sf{3(2x+5)-6x=40}

Distribute 3 :


\sf{3*2x+3*5-6x=40}


\sf{6x+15-6x=40}

subtract 15 from both sides :


\sf{6x-6x=40-15}


\sf{0x=25}


\sf{0=25}

This equation has no solutions.

User JKC
by
7.9k points
3 votes

Answer:

Explanation:

To determine the number of solutions for the equation 3(2x + 5) - 6x = 40, we can solve it step by step:

1. Simplify the equation:

Start by distributing the 3 to the terms inside the parentheses: 6x + 15 - 6x = 40.

The 6x terms cancel each other out, leaving us with 15 = 40.

2. Analyze the resulting equation:

Since 15 does not equal 40, we have a contradiction.

This means that there are no solutions to the equation.

In summary, the equation 3(2x + 5) - 6x = 40 has no solutions.

User Jprebys
by
8.1k points

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