Answer:
Each small candleholder holds 3 candles, and each large one holds 5 candles.
Explanation:
This question can be solved by a system of equations.
I am going to say that:
x is the number of candles that a small candleholder holds.
y is the number of candles that a large candleholder holds.
24 small candle holders and 3 large candle holders, using a total of 87 candles.
This means that
![24x + 3y = 87](https://img.qammunity.org/2022/formulas/mathematics/college/bgkauu873gv0vzevw71eem6xysyp21ot4l.png)
Simplifying by 3
![8x + y = 29](https://img.qammunity.org/2022/formulas/mathematics/college/jtmm64mp4l0enri9vzblwbbhuglnbngvgh.png)
![y = 29 - 8x](https://img.qammunity.org/2022/formulas/mathematics/college/fs1y8o7fzgp10lmtgd1vp80tlulos3f4wd.png)
14 small candle holders and 7 large candle holders, for a total of 77 candles.
This means that
![14x + 7y = 77](https://img.qammunity.org/2022/formulas/mathematics/college/a3zqeybglhunirnzxcbp6q0m3yln75jtq4.png)
Simplifying by 7
![2x + y = 11](https://img.qammunity.org/2022/formulas/mathematics/college/mi2fzo3w3g90mw8uwuma8270jsyks2e3kq.png)
![y = 11 - 2x](https://img.qammunity.org/2022/formulas/mathematics/college/d82emqys2e1ztrytpkh13cfcizxhjasfqp.png)
Since
![y = 29 - 8x](https://img.qammunity.org/2022/formulas/mathematics/college/fs1y8o7fzgp10lmtgd1vp80tlulos3f4wd.png)
![11 - 2x = 29 - 8x](https://img.qammunity.org/2022/formulas/mathematics/college/1xamdnrmy9hqx0z8poxqe1jptih5sv1xsh.png)
![6x = 18](https://img.qammunity.org/2022/formulas/mathematics/college/e8ypt9m92yab86kfuuuo4ius657s5veuhe.png)
![x = (18)/(6)](https://img.qammunity.org/2022/formulas/mathematics/college/pdk8vl0llep1jzav6hml7xnkyutq9o9kgk.png)
![x = 3](https://img.qammunity.org/2022/formulas/mathematics/high-school/yir5wqailux3q9a06dvay00xbhx6pnj4w0.png)
![y = 29 - 8x = 29 - 8*3 = 29 - 24 = 5](https://img.qammunity.org/2022/formulas/mathematics/college/f12smvuchiz49wnjjzjybs2yxh4ap898z7.png)
Each small candleholder holds 3 candles, and each large one holds 5 candles.