Question

Yuki weighed several soil samples, each filling a quarter liter measuring cup.

The distribution of masses has a mean of 215 g and a standard deviation of
60 g.
After recording her measurements, Yuki realized that she had forgotten to
subtract the mass of the measuring cup, which is 20 g.
What will be the mean and standard deviation of the distribution of
corrected measurements?

Answer 1

To find the mean and standard deviation of the distribution of corrected measurements, where the mass of the measuring cup (20 g) is subtracted from each measurement, you can use the following formulas:

1. For the mean (μ) of the corrected measurements:
Mean (μ) of corrected measurements = Mean (μ) of original measurements - Mass of measuring cup

Mean (μ) of corrected measurements = 215 g - 20 g = 195 g

So, the mean of the corrected measurements is 195 g.

2. For the standard deviation (σ) of the corrected measurements:
Standard Deviation (σ) of corrected measurements remains the same as the standard deviation of the original measurements.

Standard Deviation (σ) of corrected measurements = 60 g

So, the standard deviation of the corrected measurements is 60 g.