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If you can safely go around an icy banked turn at a speed of 25 m/s that has a radius of curvature of 125 meters, what is the banked angle of the turn

User Tangrs
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Where:
- \( v \) is the speed of the vehicle (25 m/s in this case).
- \( g \) is the acceleration due to gravity (approximately 9.81 m/s²).
- \( r \) is the radius of curvature of the turn (125 meters).

So, the banked angle of the turn is approximately \(26.8^\circ\).
User Macfij
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