Final answer:
The detention time in hours for each basin is approximately 21.9 hours. The horizontal flow velocity is 1.23 m/min. The overflow rate is 0.41 m/h. The weir length for each basin is 588 m. The weir loading rate is 1.23 m/d-m.
Step-by-step explanation:
To calculate the detention time in hours, we need to determine the volume of each basin. The volume of a rectangular basin can be found by multiplying the length, width, and water depth. For each basin, the volume is 28m × 7m × 13.5m = 2646 m³. The total volume of the two basins is 2 × 2646 m³ = 5292 m³. To convert the total flow rate to cubic meters per hour, we divide by 24 (hours in a day), resulting in a flow rate of 5800 m³/d ÷ 24 h/d = 241.67 m³/h.
The detention time in hours can be calculated by dividing the total volume of the basins by the flow rate. Detention time = Volume / Flow rate = 5292 m³ / 241.67 m³/h ≈ 21.9 hours.
The horizontal flow velocity in m/min can be calculated by dividing the flow rate by the cross-sectional area of each basin. The cross-sectional area is equal to the length multiplied by the width. For each basin, the cross-sectional area is 28m × 7m = 196 m². The flow velocity is 241.67 m³/h ÷ 196 m² = 1.23 m/min.
The overflow rate in m/h can be found by dividing the flow rate by the total weir length of both basins. The total weir length is equal to 2 times the length of each basin multiplied by the width. For each basin, the weir length is 2 × 28m × 3 × 7m = 588 m. The overflow rate is 241.67 m³/h ÷ 588 m = 0.41 m/h.
The weir length in m can be found by multiplying the length of each basin by the width and the factor of three. For each basin, the weir length is 28m × 3 × 7m = 588 m.
The weir loading rate in m/d-m can be found by dividing the flow rate by the surface area of each basin. The surface area is equal to the length multiplied by the width. For each basin, the surface area is 28m × 7m = 196 m². The weir loading rate is 241.67 m³/h ÷ 196 m² = 1.23 m/d-m.