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A chemist adds of a silver nitrate solution to a reaction flask. Calculate the millimoles of silver nitrate the chemist has added to the flask. Round your answer to significant digits.

User Jdhao
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The millimoles of silver nitrate the chemist added to the flask, given that the chemist adds 70.0 mL of solution to the flask is 280 millimoles

How to calculate the millimoles of silver nitrate added to the solution?

The molarity of a solution is related to the mole of the solute and volume of the solution by the following equation:

Molarity of solution = mole of solute / volume of solution

Thus,

Mole of solute = molarity of solution × volume of solution

Using the above formula, we can calculated the millimoles of silver nitrate added to the solution. This is shown below:

  • Volume of silver nitrate solution = 70 mL = 70 / 1000 = 0.07 L
  • Molarity of silver nitrate solution = 4.0 M
  • Millimole of silver nitrate solution added =?

Mole of solute = molarity of solution × volume of solution

= 4.0 × 0.07

= 0.28 mole

Multiply by 1000 to express in millimole

= 0.28 × 1000

= 280 millimoles

Complete question:

A chemist adds 70.0mL of a 4.0 M silver nitrate, AgNO3, solution to a reaction flask. Calculate the millimoles of silver nitrate the chemist has added to the flask. Round your answer to significant digits.

User Morganis
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