Question

If you had thrown the pennies down from the observation deck 321m above street level at an initial velocity of 1.99m/s, determine their speed as they reach the ground.

Answer 1

Answer:79.3 m/s

Step-by-step explanation:

Answer 2

Answer: 79.3 m/s

Explanation: Use the equation V^2-Vo^2=2a(ΔY)

We know that the initial velocity is 1.99 m/s, so that is our Vo. We also are given that the height of the deck is 321, so therefore, our delta y is 321. Finally, our acceleration is 9.81 m/s^2 since that is the acceleration of gravity during free fall. We are solving for the final velocity (V)

So, our equation is V^2-(1.99^2)=2(9.8)(321)

Next, V^2-(3.96)=6291.6

V^2=6295.56

Take the square root of both sides, and V=79.3 m/s