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How many calories of heat are needed to raise the temperature of 45.0 g of diethyl ether from 5.0 ∘C to 18.0 ∘C ?Diethyl ether, a substance once used as a general anesthetic, has a specific heat of 0.895 cal/(g⋅∘C) .

1 Answer

5 votes

Answer:

approximately 533 calories.

Step-by-step explanation:

To calculate the amount of heat required to raise the temperature of a substance, we can use the formula:

q = m * c * ΔT

Where:

q = heat energy (in calories)

m = mass of the substance (in grams)

c = specific heat capacity (in cal/(g⋅∘C))

ΔT = change in temperature (in ∘C)

Given:

m = 45.0 g

c = 0.895 cal/(g⋅∘C)

ΔT = (18.0 ∘C) - (5.0 ∘C) = 13.0 ∘C

Using the formula:

q = (45.0 g) * (0.895 cal/(g⋅∘C)) * (13.0 ∘C)

q = 532.575 cal

Therefore, approximately 533 calories of heat are needed to raise the temperature of 45.0 g of diethyl ether from 5.0 ∘C to 18.0 ∘C.

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