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Find angle A !!

*law sines and cosines*
2.

Find angle A !! *law sines and cosines* 2.-example-1

2 Answers

4 votes

Answer:

HI,

Explanation:

Using law of sinus:


\frac{sin (\widehat{A})}{BC} =\frac{sin (\widehat{B})}{AC} \\\\sin(\widehat{A})=(25*sin(62^o))/(28) =0.78893406...\\\\m\angle{A}=arcsin(0.7889...)=52.031216..^o

User Mahathi Vempati
by
7.7k points
6 votes

Answer:

∠ A ≈ 52°

Explanation:

using the law of sines in Δ ABC


(a)/(sinA) =
(b)/(sinB) =
(c)/(sinC)

where a, b and c are the sides opposite ∠ A, ∠ B and ∠ C

here a = 25 and b = 28

using the first 2 ratios from the law of sines to find ∠ A


(25)/(sinA) =
(28)/(sin62) ( cross- multiply )

28 × sinA = 25 × sin62° ( divide both sides by 28 )

sinA =
(25sin62)/(28) , then

∠ A =
sin^(-1) (
(25sin62)/(28) ) ≈ 52° ( to the nearest degree )

User EricM
by
7.6k points

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