Question

There are two aircraft​ carriers, A and​ B, and carrier A is longer in length than the carrier B. The total length of these two carriers is 2198 ​feet, while the difference of their lengths is only 14 feet. If a football field has a length of 100 ​yards, determine the length of carrier A in terms of the number of football fields.

Answer 1

Let's use algebra to solve this problem. Let the length of carrier A be represented by "x" feet and the length of carrier B be represented by "y" feet.

From the information given, we have two equations:

1. x + y = 2198 (The total length of the carriers is 2198 feet)

2. x - y = 14 (The difference in their lengths is 14 feet)

Now, let's solve this system of equations. We can do this by adding the two equations together:

(x + y) + (x - y) = 2198 + 14

This simplifies to:

2x = 2212

Now, divide both sides by 2 to solve for x:

2x/2 = 2212/2

x = 1106

So, the length of carrier A (x) is 1106 feet. To express this length in terms of the number of football fields, we need to convert feet to yards since a football field is measured in yards.

1 yard = 3 feet

Therefore, carrier A's length in yards is:

1106 feet / 3 = 368.67 yards

Now, to express this in terms of the number of football fields:

368.67 yards / 100 yards (length of a football field) = 3.6867 football fields

So, the length of carrier A is approximately 3.6867 football fields.