To determine how far above the surface of liquid C the top of a fifth ball with a density of 0.25 g/cm³ would likely be located, we need to consider the principle of buoyancy. Buoyancy is the upward force exerted on an object submerged in a fluid (liquid or gas), and it depends on the difference in density between the object and the fluid.
Let's assume that the fifth ball is fully submerged in liquid C. We can use the following formula to calculate the depth it will sink to:
Buoyant Force = Weight of the Object
The buoyant force is equal to the weight of the displaced liquid. The weight of the object is its mass multiplied by the acceleration due to gravity (9.81 m/s²).
1. First, let's convert the density of the ball to kg/cm³, which is the same as 250 kg/m³ (since 1 g/cm³ = 1000 kg/m³).
2. Next, let's calculate the volume of the fifth ball. We'll assume it has a uniform shape (e.g., a sphere) and a known diameter or radius.
3. Then, calculate the weight of the fifth ball using its density and volume.
4. Finally, equate the buoyant force to the weight of the ball and solve for the depth (distance above the surface) at which the ball will likely be located.
Please provide the diameter or radius of the fifth ball, and I can assist you with the calculation.