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What is the solution set in interval notation?

Express in integers or reduced fractions.

4 - 7 |7x - 7| \leqslant 8


User Serty Oan
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1 Answer

4 votes

Answer:

x ∈ (-∞, 45/49] ∪ [53/49, +∞)

Explanation:

To find the solution set for the inequality 4 - 7 |7x - 7| ≤ 8, we can break it down into two cases based on the absolute value.

Case 1: When (7x - 7) ≥ 0

In this case, we can remove the absolute value and rewrite the inequality as 4 - 7(7x - 7) ≤ 8. Simplifying further, we get 4 - 49x + 49 ≤ 8, which becomes -49x + 53 ≤ 8. Rearranging the terms, we have -49x ≤ -45, and dividing by -49 (remembering to flip the inequality sign since we're dividing by a negative number), we get x ≥ 45/49.

Case 2: When (7x - 7) < 0

Here, we need to flip the inequality when removing the absolute value, resulting in 4 + 7(7x - 7) ≤ 8. Expanding and simplifying, we have 4 + 49x - 49 ≤ 8, which becomes 49x - 45 ≤ 8. Solving for x, we get x ≤ 53/49.

Combining the solutions from both cases, we have the solution set in interval notation:

x ∈ (-∞, 45/49] ∪ [53/49, +∞)

This means that x can take any value less than or equal to 45/49 or any value greater than or equal to 53/49, including both of these endpoints.

User Gnodab
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