![= \tt8x + 12 = -3x + 3 + 31](https://img.qammunity.org/2022/formulas/mathematics/high-school/juixzdrdawjts4l98jh5t7uussrcmyj53o.png)
![=\tt 8x + 12 + 3x = 3 + 31](https://img.qammunity.org/2022/formulas/mathematics/high-school/9dw8oo13qi6ipgyad79x61py40lfj0kxsv.png)
![= \tt11x + 12 = 34](https://img.qammunity.org/2022/formulas/mathematics/high-school/gpnv44zprr67qlu5xqhm4ljids4vgpsgyy.png)
![= \tt11x = 34 - 12](https://img.qammunity.org/2022/formulas/mathematics/high-school/udhwsc742jbzjl3ycg4r0c5bfaihcwz1mx.png)
![= \tt11x = 22](https://img.qammunity.org/2022/formulas/mathematics/high-school/z7kio06m2cgv2watra07rratzxvk9zbrid.png)
![=\tt x = (22)/(11)](https://img.qammunity.org/2022/formulas/mathematics/high-school/ee0lsempxyhyyb7rdivf3mm33gpzcfqqcf.png)
![\hookrightarrow\color{plum}\tt x = 2](https://img.qammunity.org/2022/formulas/mathematics/high-school/kuurafjd6g5ybi04p6orl410i50xf9923e.png)
Thus, the value of x = 2
Let us check whether or not we have found out the correct value of x, by placing 2 in the place of x :
![=\tt 8 * 2 + 12 = - 3 * 2 + 3 + 31](https://img.qammunity.org/2022/formulas/mathematics/high-school/sgn7be4tk76pepa9n7jj492kmm0mnxt2p5.png)
![= \tt16 + 12 = - 6 + 34](https://img.qammunity.org/2022/formulas/mathematics/high-school/ssjvhf7sk96baj3qi61csh59vf6ul58adf.png)
![= \tt28 = 28](https://img.qammunity.org/2022/formulas/mathematics/high-school/saqpxyepm25fm62yt6l1jwtyzpwjidai5t.png)
Since the Left Hand Side and the Right Hand Side of the equation are equivalent, we can conclude that we have found out the correct value of x.
▪︎Therefore, the value of x = 2