Question

Find an equation for the line with the given properties. Express your answer using either the general form or the​ slope-intercept form of the equation of a line.

Parallel to the line y=6x​; containing the point (−5,5)

Answer 1

To find the equation of a line parallel to the line y = 6x and containing the point (-5, 5), you can use the point-slope form of the equation of a line:

y - y1 = m(x - x1)

Where:

(x1, y1) is the given point (-5, 5).

m is the slope of the line.

Since the desired line is parallel to y = 6x, it will have the same slope as y = 6x, which is 6.

Now, plug in the values:

y - 5 = 6(x - (-5))

Simplify:

y - 5 = 6(x + 5)

Now, you can express it in either the slope-intercept form (y = mx + b) or the general form (Ax + By = C).

Slope-intercept form:

y = 6x + 35

General form:

-6x + y = 35

Explanation:

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