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Find exterior angle x in abc

PLEASE HELP

Find exterior angle x in abc PLEASE HELP-example-1
User Rogerio
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Answer:

Explanation:

160º is an exterior angle of the Δ ABC. So, by using the exterior angle theorem, we have, ∠BAC + ∠ABC = 160º x + 3x = 160º 4x = 160º x = 40º Therefore, ∠BAC = x = 40º and ∠ABC = 3xº = 120º

User Return
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