Question

a body is projected from the ground at an angle of theta to the horizontal with a velocity of 30 m per second square it reaches a maximum height at 11.20 5m now calculate the value of theta the time taken to strike the ground and the range​

Answer 1

30°

3 s

77.94 m

Step-by-step explanation:

a) Given in the y direction:

u = 30 sin θ m/s

v = 0 m/s

a = -10 m/s²

s = 11.25 m

Find: θ

v² = u² + 2as

(0)² = (30 sin θ)² + 2(-10)(11.25)

θ = 30°

b) Given in the y direction:

s = 0

u = 30 sin 30° = 15 m/s

a = -10 m/s²

Find: t

s = u t + ½ a t²

0 = (15) t + ½ (-10) t²

t = 3 s

c) Given in the x direction:

u = 30 cos 30° = 25.98 m/s

a = 0 m/s²

t = 3 s

Find: s

s = u t + ½ a t²

s = (25.98) (3) + ½ (0) (3)²

s = 77.94 m