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what is the equation in slope-intercept form of the line that passes through the points (-4,1) and (-3,0)?

User Leonixyz
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1 Answer

7 votes

Answer:

y = -x - 3

Explanation:

The general equation for the slope-intercept form is given by:

y = mx + b, where

  • m is the slope,
  • and b is the y-intercept.

Finding m (the slope):

We can find the slope (m) using the slope formula, which is given by:

m = (y2 - y1) / (x2 - x1), where

  • m is the slope,
  • (x1, y1) is one point on the line,
  • and (x2, y2) is another point.

Thus, we can find the slope (m) by substituting (-4, 1) for (x1, y1) and (-3, 0) for (x2, y2):

m = (0 - 1) / (-3 - (-4))

m = -1 / (-3 + 4)

m = -1 / 1

m = -1

Thus, the slope is -1.

Finding b (the y-intercept):

Now we can find b (the y-intercept) by plugging in -1 for m and (-4, 1) for (x, y) in the slope-intercept form:

1 = -(-4) + b

(1 = 4 + b) - 4

-3 = b

Thus, the y-intercept is -3.

Writing the equation of the line in slope-intercept form:

Therefore, y = -x - 3 is the equation of the line in slope-intercept form that passes through the points (-4, 1) and (-3, 0).

User Anand
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