Question

Use the substituion method to determine the solution type of the following system

3y-6x=3
y=2x+1

Answer 1

The solution is (x, y) = (0, 1)

Explanation:

3y - 6x = 3 (1)

y = 2x + 1 (2)

Let's substitute the value of y (2x + 1) into the first equation.

3(2x + 1) - 6x = 3

6x + 3 - 6x = 3

0 = 0; Hence, x = 0.

Substituting 0 for x in any of the 2 equations (I will use 2)

y = 2x + 1

y = 0 + 1

y = 1.

The solution is (x, y) = (0, 1)

to double check;

y=2x+1

1 = 2*0 + 1

1 = 1

This concludes that the answer is (x, y) = (0, 1).

Hope this helped!