Answer:
The solution is (x, y) = (0, 1)
Explanation:
3y - 6x = 3 (1)
y = 2x + 1 (2)
Let's substitute the value of y (2x + 1) into the first equation.
3(2x + 1) - 6x = 3
6x + 3 - 6x = 3
0 = 0; Hence, x = 0.
Substituting 0 for x in any of the 2 equations (I will use 2)
y = 2x + 1
y = 0 + 1
y = 1.
The solution is (x, y) = (0, 1)
to double check;
y=2x+1
1 = 2*0 + 1
1 = 1
This concludes that the answer is (x, y) = (0, 1).
Hope this helped!