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What equation of a line has a Slope of 3 and contains the points (-5, 7)

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Answer:

Explanation:

You can find the equation of a line with a given slope that passes through a specific point using the point-slope form of a linear equation:

y - y₁ = m(x - x₁)

Where:

(x₁, y₁) is the given point on the line.

m is the slope of the line.

In your case, you have a slope of 3 and a point (-5, 7). Plug these values into the formula:

y - 7 = 3(x - (-5))

Now, simplify the equation:

y - 7 = 3(x + 5)

Distribute 3 on the right side:

y - 7 = 3x + 15

Now, isolate y by adding 7 to both sides:

y = 3x + 15 + 7

y = 3x + 22

So, the equation of the line with a slope of 3 that passes through the point (-5, 7) is:

y = 3x + 22

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