Question

Write the coordinates for the center of the hyperbola: (y-2)²/16-(x+1)²/144=1

Answer 1

Hi,

Explanation:

`f(x,y)=((y-2)^2)/(16) -((x+1)^2)/(144)-1=0\\ \\\\\frac{\partial{f(x,y)}}{\partial x} =(-2)/(144) (x+1)=0\ \Longrightarrow\ x=-1\\\\\frac{\partial{f(x,y)}}{\partial y} =(2)/(16) (y-2)=0\ \Longrightarrow\ y=2\\\\`

center is (-1,2)