201k views
3 votes
Find the nature of the roots of 3x² -4√3x +4=0.

1 Answer

6 votes

Answer:

Explanation:

To determine the nature of the roots of the quadratic equation 3x² - 4√3x + 4 = 0, we can use the discriminant. The discriminant (D) is calculated using the formula D = b² - 4ac, where a, b, and c are the coefficients of the quadratic equation in the form ax² + bx + c = 0.

Let's apply this formula to the given equation:

a = 3, b = -4√3, c = 4

D = (-4√3)² - 4(3)(4)

= 48 - 48

= 0

The discriminant is equal to 0.

Now, let's determine the nature of the roots based on the value of the discriminant:

1. If D > 0, the equation has two distinct real roots.

2. If D = 0, the equation has two identical real roots (also called a "double root").

3. If D < 0, the equation has two complex conjugate roots.

In this case, since the discriminant is 0, the equation has two identical real roots or a double root.

Therefore, the nature of the roots of the equation 3x² - 4√3x + 4 = 0 is that it has two identical real roots or a double root.

User Eduardo Bergel
by
7.9k points

Related questions

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories