Question

An object of mass 0.80 kg is moving in a straight line at a velocity of 2.0 m/s. A force is exerted on the object, in the direction of motion, for a period of 1.0 minute and the velocity of the object increases to 6.0 m/s.What force is exerted on the object?​

Answer 1

0.053 N

Step-by-step explanation:

F = ma

m = 0.80 kg

t = 1 min = 60 sec

a = (Vf - Vi)/t = (6.0 m/s - 2.0 m/s) / 60 sec = 0.0667 m/s²

F = (0.80 kg)(0.0667 m/s²) = 0.053 N