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If f(y)=y^6/6lny-y^6/36, find f'(y)

User AgentX
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1 Answer

13 votes
13 votes

It looks like you have


f(y)=(y^6)/(6\ln(y))-(y^6)/(36)

Differentating gives


f'(y)=(6y^5*6\ln(y)-6y^6*\frac1y)/((6\ln(y))^2)-(6y^5)/(36)= -(y^5\left(\ln^2(y)-6\ln(y)+1\right))/(6\ln^2(y))

User Damanpreet Singh
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