Question

If f(y)=y^6/6lny-y^6/36, find f'(y)

Answer 1

It looks like you have

`f(y)=(y^6)/(6\ln(y))-(y^6)/(36)`

Differentating gives

`f'(y)=(6y^5*6\ln(y)-6y^6*\frac1y)/((6\ln(y))^2)-(6y^5)/(36)= -(y^5\left(\ln^2(y)-6\ln(y)+1\right))/(6\ln^2(y))`