Question

What is the equation of the line that passes through the point (- 2, - 8,) and has a slope of 1 ?

Answer 1

`(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-8})\hspace{10em} \stackrel{slope}{m} ~=~ 1 \\\\\\ \begin{array}ll \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-8)}=\stackrel{m}{1}(x-\stackrel{x_1}{(-2)}) \implies y +8 = 1 ( x +2) \\\\\\ y+8=x+2\implies {\Large \begin{array}{llll} y=x-6 \end{array}}`

Answer 2

y = x - 6

Explanation:

y - y = m (x - x)

y - - 8 = 1 (x - - 2)

y + 8 = x + 2

y = x + 2 - 8

y = x - 6