Question

A system of equations is given.

−2y = 10 − 5x
−3y = −4x +15

Solve for (x, y) using the elimination method. Show all work.

Answer 1

−2y = 10 − 5x

−3y = −4x +15

5x-2y=10

4x-3y=15

elimination

3(5x-2y=10)-----> 15x-6y=30

-2(4x-3y=15)----> -8x+6y=-30

--->x=0

4x-3y=30

4*0-3y=15

-y= 15/3 =5

y= -5

solution (0, -5)

Explanation: