Question

if 7.90 mol of C5H12 reacts with excess O2, how many moles of CO2 will be produced by the following combustion reaction?

Answer 1

If 7.9 moles of C₅H₁₂ reacts with excess O₂, 39.5 moles of CO₂ will be produced.

Step-by-step explanation:

The balanced reaction is:

C₅H₁₂ + 8 O₂ → 5 CO₂ + 6 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

• C₅H₁₂: 1 moles
• O₂: 8 moles
• CO₂: 5 moles
• H₂O: 6 moles

Then you can apply the following rule of three: if by stoichiometry 1 mole of C₅H₁₂ produces 5 moles of CO₂, then 7.9 moles of C₅H₁₂ will produce how many moles of CO₂?

`amount of moles of CO_(2) =(7.9 moles of C_(5)H_(12)*5 moles of CO_(2) )/(1 mole of C_(5)H_(12) )`

amount of moles of CO₂= 39.5 moles

If 7.9 moles of C₅H₁₂ reacts with excess O₂, 39.5 moles of CO₂ will be produced.