Question

If 7.90 mol of C5H12 reacts with excess O2, how many moles of CO2 will be produced by the following combustion reaction?

C5H12+8O2=6H2O+5CO2

Answer 1

moles CO₂ produced from combustion of 7.9 mole of C₅H₁₂ = 39.5 moles CO₂

Step-by-step explanation:

C₅H₁₂ + 8O₂ => 6H₂O + 5CO₂

Given: 7.9moles excess _____ ? moles

From Equation, 1 mole C₅H₁₂ =============> 5 moles CO₂

Given 7.9 mole C₅H₁₂ =============> X

Solving for 'X' using ratio and proportion ...

1mole C₅H₁₂ / 7.9mole C₅H₁₂ = 5mole CO₂ / X

=> X = 5 mole CO₂ x 7.9mole C₅H₁₂ / 1mole C₅H₁₂ = 39.5 moles CO₂

≅ 40 moles CO₂ (2 sig. figs.)