Question

a 7.50g sample of iron was heated from 27°c to 85°c. it observed 876.4J of energy as heat. what is the specific heat of iron

Answer 1

2.01 J/g°C.

Step-by-step explanation:

To determine the specific heat of iron, we can use the formula:

q = m * c * ΔT

where:

q = heat energy absorbed or released

m = mass of the substance (in grams)

c = specific heat capacity of the substance (in J/g°C)

ΔT = change in temperature (in °C)

Given information:

Mass of iron (m) = 7.50g

Initial temperature (T1) = 27°C

Final temperature (T2) = 85°C

Heat energy (q) = 876.4J

We need to rearrange the formula to solve for the specific heat capacity (c):

c = q / (m * ΔT)

Now we can substitute the values into the formula:

c = 876.4J / (7.50g * (85°C - 27°C))

Simplifying the equation:

c = 876.4J / (7.50g * 58°C)

c ≈ 2.01 J/g°C

Therefore, the specific heat of iron is approximately 2.01 J/g°C.