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Two automobile start out at the same time from cities 595 km apart. If the speed of one is 8/9 of the other and if they meet in 7 hours, what is the speed of each? ​

User Ringding
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1 Answer

2 votes

Answer:

45

Explanation:

Let's assume the speed of the slower car is x km/h. Since the speed of the other car is 8/9 of the speed of the slower car, the speed of the faster car is (8/9)x km/h.

We know that the two cars meet after traveling for 7 hours, and the total distance between the two cities is 595 km.

To find the speed of each car, we can use the formula:

distance = speed × time

For the slower car: distance = x km/h × 7 hours

For the faster car: distance = (8/9)x km/h × 7 hours

Since the total distance between the two cities is 595 km, we can set up the equation:

x km/h × 7 hours + (8/9)x km/h × 7 hours = 595 km

Now, we can solve for x:

7x + (8/9)x × 7 = 595

Multiplying both sides by 9 to eliminate the fraction, we get:

63x + 56x = 5355

119x = 5355

x = 5355/119

x ≈ 45

Therefore, the speed of the slower car is approximately 45 km/h, and the speed of the faster car is approximately (8/9) × 45 = 40 km/h.

User Pacreely
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