Question

When the traffic light turns green, a car accelerates from rest at 4.0 m/s^2 for 3.0 seconds. What distance is covered by the car during that time? a) Provide the distance covered.

Answer 1

The car covers a distance of 18.0 meters during the 3.0 seconds of acceleration.

Step-by-step explanation:

`\[s = u * t + (1)/(2) a * t^2\]`

Where:

- s is the distance covered by the car.

- u is the initial velocity (which is 0 m/s since the car starts from rest).

- a is the acceleration (given as 4.0 m/s^2).

- t is the time duration (given as 3.0 seconds).

Given that u = 0, the equation simplifies to:

`\[s = (1)/(2) a * t^2\]`

Substituting the given values, we get:

`\[s = (1)/(2) * 4.0 \, \text{m/s}^2 * (3.0 \, \text{s})^2\]`

The car covers a distance of 18.0 meters during the 3.0 seconds of acceleration.