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For the function x^2 - 3, find the slope of the tangent line at x = -8

1 Answer

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Explanation:

f(x)=x^2-3

at x=-8 the value of the function is 61

y=61

the slope of the tangent to the function at the point

(-8,61) is diffentiating the function and substituting point in it after differentiation we get 2x

the slope of the tangent is 2×-8 that is -16

answer is -16

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