Question

If the motor is 75% efficient, and 12 KJ of electrical energy is converted to mechanical work, then the heat lost in the motor is A) 3 KJ B) 4 KJ C) 9 KJ D) 15 KJ

Answer 1

B

Step-by-step explanation:

75%= 3/4= efficient= 12kj

75%=3/4= 3(1/4)

if 3/4 = 12kj= 3(4kj)

then 100%=16kj

so heat lost= 100%-75%= 25%

so 25%=1/4 = 4kj