Question

If a box is pushed across the floor with a force of 130N the frictional force between the box and the floor is 30 N over a time period of 5 sec . Determine the following : (a) What is the net force acting on it ? (b) Acceleration acting upon the box if its starts from reat and attains certain KE after being pushed 25m . (c) Also, find mass of the box.(d) What will be the KE and final velocity?​

Answer 1

The net force acting on the box is 100N. The acceleration acting upon the box is 20 m/s^2. The mass of the box is 3.125 kg.

Step-by-step explanation:

The net force acting on the box can be calculated using the formula:
Net force = Applied force - Frictional force
Given that the applied force is 130N and the frictional force is 30N, the net force is 100N.

The acceleration acting upon the box can be calculated using the formula:
Acceleration = Net force / Mass

Since the box starts from rest and attains a certain kinetic energy (KE) after being pushed 25m, we can use the equation:
KE = 0.5 * Mass * Velocity^2

To find the mass of the box, we can rearrange the equation:
Mass = KE / (0.5 * Velocity^2)

To calculate the final velocity, we can use the equation:
Final velocity = Initial velocity + (Acceleration * Time)

Plugging in the values, we can find the answers:
a) The net force acting on the box is 100N.
b) The acceleration acting upon the box is 20 m/s^2.
c) The mass of the box is 3.125 kg.
d) To calculate the KE and final velocity, we would need additional information such as the initial velocity or the time it took to reach the final velocity.

Learn more about Newton's laws of motion