Question

three consecutive odd interfere are such that the sum of the first and second is 31 less than 3 times the third

Answer 1

21, 23, 25

Explanation:

You want 3 consecutive odd integers such that the sum of the first two is 31 less than 3 times the third.

Setup

Let x represent the middle integer. Then the first is (x-2) and the third is (x+2). The given relation can be expressed as ...

x +(x -2) = 3(x +2) -31

Solution

2x -2 = 3x -25 . . . . . . . . simplify

23 = x . . . . . . . . . . add 25-2x

The three integers are 21, 23, and 25.

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Additional comment

21 +23 + 31 = 75 = 3(25)

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