Answer:
To calculate the net electric flux through a cube placed in a uniform electric field, you can use Gauss's Law, which states that the electric flux (Φ) through a closed surface is equal to the electric field (E) times the surface area (A) and is also equal to the enclosed charge (Q) divided by the permittivity of free space (ε₀):
Φ = E * A = Q / ε₀
In this case, the cube has a side length of 1 meter, so its surface area (A) is 6 square meters (since there are 6 faces of a cube). The electric field (E) is given as 10⁴ N/C î, and there is no mention of any enclosed charge (Q) within the cube.
Now, calculate the electric flux:
Φ = E * A = (10⁴ N/C) * (6 m²) = 60,000 N m²/C
The unit of electric flux is N m²/C.
So, the net electric flux through the cube is 60,000 N m²/C, which is not one of the provided answer choices. However, if you convert this to the preferred unit of electric flux, which is N m² c⁻¹, you get:
60,000 N m²/C = 60,000 N m² c⁻¹
So, the answer closest to this value is (c) 5 x 10⁴ N m² c⁻¹.
Step-by-step explanation:
Have great day!