Question

Use the piecewise function below to evaluate the points f(–3), f(0), and f(–1).

{9x,x−4,x<−1x≥−1
Question 17 options:

f(–3) = –7, f(0) = –0, and f(–1) = 5


f(–3) = –27, f(0) = –4, and f(–1) = 5


f(–3) = –7, f(0) = –4, and f(–1) = –1


f(–3) = –27, f(0) = –4, and f(–1) = –5

Answer 1

Given:

The piecewise function is:

`f(x)=\begin{cases}9x & \text{ if } x<-1 \\ x-4 & \text{ if } x\geq -1 \end{cases}`

To find:

The values of
`f(-3),f(0), f(-1)`.

Solution:

In the given piecewise function,

`f(x)=9x` for
`x<-1` and
`f(x)=x-4` for
`x\geq -1`.

Putting
`x=-3` in
`f(x)=9x`, we get

`f(-3)=9(-3)`

`f(-3)=27`

Putting
`x=0` in
`f(x)=x-4`, we get

`f(0)=0-4`

`f(0)=-4`

Putting
`x=-1` in
`f(x)=x-4`, we get

`f(-1)=-1-4`

`f(-1)=-5`

The required values are
`f(-3)=27,f(0)=-4,f(-1)=-5`.

Therefore, the correct option is D.