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A fireworks shell is accelerated from rest to a velocity of 65.0 m/s over a distance of 0.250 m. How long did the acceleration last?

User Hmadrigal
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1 Answer

2 votes

Answer:

8450 m/s²

Step-by-step explanation:

To calculate the time it took for the fireworks shell to accelerate from rest to a velocity of 65.0 m/s over a distance of 0.250 m, we can use the formula:

[ t = \frac{{v_f - v_0}}{{a}} ]

Where:

( t ) is the time of acceleration,

( v_f ) is the final velocity (65.0 m/s),

( v_0 ) is the initial velocity (0 m/s), and

( a ) is the acceleration.

First, let’s calculate the acceleration using the formula:

[ a = \frac{{v_f^2 - v_0^2}}{{2 \cdot \Delta x}} ]

Substituting the given values, we have:

[ a = \frac{{(65.0 , \text{{m/s}})^2 - (0 , \text{{m/s}})^2}}{{2 \cdot 0.250 , \text{{m}}}} ]

Simplifying this expression gives us an acceleration of 8450 m/s²

User Cameron Kerr
by
8.1k points
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