Question

A 44g sample of liquid water at 18C ends up as ice -14C. How much energy is involved in this change?

Answer 1

Q = -5913.6 J

Step-by-step explanation:

Given that,

Mass of the sample, m = 44 g = 0.044 kg

Initial temperature = 18°C

Final temperature = -14°C

We need to find the energy involved in this change. The energy involved in this process is given by :

`Q=mc\Delta T`

c is specific heat of water

`Q=0.044* 4200* (-14-18)\\\\Q=-5913.6\ J`

So, 5913.6 J of energy is involved in this change.