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Let V = (2.00m)i + (6.00m)j − (3.00m)k. The magnitude of V is:

User Guysigner
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Final answer:

The magnitude of the vector V = (2.00m)i + (6.00m)j - (3.00m)k is computed as the square root of the sum of the squares of its components. Upon calculation, it results in 7 meters.

Step-by-step explanation:

The magnitude of a vector is the length or size of the vector. This can be calculated by the formula √(X^2 + Y^2 + Z^2) where X, Y and Z are the horizontal, vertical, and z-axis components of the vector respectively. In this case, the vector V = (2.00m)i + (6.00m)j - (3.00m)k. So, the magnitude |V| would be √((2.00m)^2 + (6.00m)^2 + (-3.00m)^2) which evaluates to √(4 + 36 + 9)m = √49m = 7m.

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User Fedor Soldatkin
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