79.8k views
4 votes
What is the slope on a cordinate plane between 6,1 & -4,-2

User Ezer K
by
8.8k points

1 Answer

4 votes

Answer:


(3)/(10)

Explanation:

The slope of a line between two points
(x_1,y_1) and
(x_2,y_2) is defined as:


m = (\Delta y)/(\Delta x) = (y_2 - y_1)/(x_2 - x_1)

Note that the symbol
\Delta just means "change in", so we are representing "rise" as
\Delta y (change in y) and "run" as
\Delta x (change in x).

From the given points
(6,1) and
(-4, -2), we can identify the following variable values:


  • x_1 = 6

  • y_1 = 1

  • x_2 = -4

  • y_2 = -2

Now, we can plug these into the slope definition:


m = (-2 - 1)/(-4 - 6)


m = (-3)/(-10)


\boxed{m = (3)/(10)}

What is the slope on a cordinate plane between 6,1 & -4,-2-example-1
User Prateeksarda
by
8.0k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories