Answer:
Mass of carbon dioxide = 0.30 g / 30.07 g/mol x 44.01 g/mol
Explantion
To calculate the maximum mass of carbon dioxide produced, we need to determine the limiting reactant between ethane (C2H6) and oxygen (O2). The limiting reactant is the reactant that is completely consumed and determines the maximum amount of product formed. Here's how we can calculate it:
1. Find the molar masses of ethane and oxygen. The molar mass of C2H6 (ethane) is approximately 30.07 g/mol, and the molar mass of O2 (oxygen) is approximately 32.00 g/mol.
2. Convert the masses of ethane and oxygen to moles. To do this, divide the mass of each substance by its molar mass:
Moles of ethane = Mass of ethane / Molar mass of ethane
= 0.30 g / 30.07 g/mol
Moles of oxygen = Mass of oxygen / Molar mass of oxygen
= 1.53 g / 32.00 g/mol
3. Determine the mole ratio of ethane to carbon dioxide. The balanced chemical equation for the reaction is:
C2H6 + O2 -> CO2 + H2O
From the equation, we can see that 1 mole of ethane produces 1 mole of carbon dioxide.
4. Calculate the moles of carbon dioxide that could be produced by the reaction. Since the mole ratio of ethane to carbon dioxide is 1:1, the number of moles of carbon dioxide produced is equal to the number of moles of ethane:
Moles of carbon dioxide = Moles of ethane
= 0.30 g / 30.07 g/mol
5. Convert the moles of carbon dioxide to mass. To do this, multiply the moles of carbon dioxide by its molar mass:
Mass of carbon dioxide = Moles of carbon dioxide x Molar mass of carbon dioxide
= 0.30 g / 30.07 g/mol x 44.01 g/mol
6. Perform the calculation to find the maximum mass of carbon dioxide:
Mass of carbon dioxide = 0.30 g / 30.07 g/mol x 44.01 g/mol
Make sure to carry out the multiplication and division correctly using a calculator or spreadsheet software.
By following these steps, you can calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction.
I hope this helps you calculate the maximum mass of carbon dioxide!
Step-by-step explanation: